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Comments
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I have nothing but feels for you, man. I’ve been living this for like two weeks.
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zuley196y@broseph thank you for the feels at least. Currently taking a break before I go back to tackle this. Hoping we both figure this out.
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bahua129056y@zuley
I very highly recommend using a REST client like insomnia to test it, as it will cut through all the http handling for you and just show you what you need. -
zuley196y@devTea I really appreciate your suggestion. I looked up both clients and I kind of get it but I think I need to take a step back. Maybe I'm not handling the query results right. When I echo json_encode($query_results) what prints is the actual query string (SELECT FROM WHERE etc.). I feel like that shouldn't happen...? Also when I use fetchAll() nothing happens. I'm looking at w3schools website and they are using ->prepare() and ->execute() and ->get_results() which I am not. Is this where I'm going wrong? The way I am running the query is $results = $db->query($query); return $results. To print the results I am using a foreach loop in a printResults function and they print okay in a table format. But they dont seem to get passed to the json object. I am not looping when I am trying to create the object (in a separate function) bc I thought fetchAll() would do that, but as I said that doesn't work. Sorry for the long post but thanks for reading.
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"i just want to understand this"
there's your problem.
repeat after me: "Javascript is not understood nor written. Javascript is referenced from other people's online repos that you have no control over, or, if you must, copypasted from random google search results."
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I cant get a JSON object out of my query results!! I have been trying all day and I'm so frustrated and sad. I'm new to JavaScript, AJAX, and JSON. I just want to understand this. I've seen videos, tutorials, but I never get the expected results with jason_encode. And on the client side I don't even know if the request is good since I can't make the JSON object. :(
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