GUYS WE HAVE BEEN WRITING FOR LOOPS IN JAVA WRONG THE WHOLE TIME. Here is how it should be done correctly...
int i = 0;
for(;(i<10) ? true : false;)
{
i++;
System.out.println(i);
}

Jokes aside though does anyone have any more horrid ways to write this?

don't initialize i

Have a loop counter factory giving back a loop counter value object then create a loop counter value changed event handler on the loop counter then send an event

System.out.println(0);
System.out.println(1);
System.out.println(2);
System.out.println(3);
System.out.println(4);
System.out.println(5);
System.out.println(6);
System.out.println(7);
System.out.println(8);
System.out.println(9);

@ilikeglue care to write an example?

I thought you were serious for a moment... I was about to say what the hell is wrong with you lol.

@ilikeglue that sounds just like a Java only thing ;D

Overcomplicating simple stuff for the sake of abstraction

I was gonna say you can while loop with goto statement.
But goto doesn't exist in Java..

That hurt. Even as a joke. Lol

int i=10;
while(true){
try{
//code here
int j = 1/--i;
}catch(Throwable t){
//end of loop
}
}

@lotd

TAG: while(true){
//code
continue TAG;
}

You are welcome :^)

@ilikeglue isnt an IterableFactory more abstract? 🤔

int i = 0;
for (;;) {
i = i + 1;
if (i <= 10) {
//Do stuff
} else {
break;
}
}

How about this? Note that the i++ is at the beginning, because who needs 0 indexed stuff, duh! (I would bever say that, but hey you asked for the worst we can think of...)

@Zennoe *loads gun*

Worst thing I've seen, C++:
int i; int stop = 0;
for ( ; stop != 1; i++ ) {
// some code...
stop = (condition) ? 1 : 0;
}

Oh and 'i' wasn't actually used.

@lotd not with that attitude.

@Spacebrain hahahah that is horrid!

@Zennoe *triggered*

int i = 0;

for(;;) {
i++;

if(i == 10)
break;
}

//my mind gave birth this senseless abortion

bool success = repeat(10, new Callable<void>() {
public Integer call() {
System.out.println("repeating this");
});

boolean repeat(int times, Callable<T> func) {
return! repeat(0, times, func);
}

int repeat(int i, times, Callable<T> func) {
func.call();
return i < times ? repeat(++i, times, func) : 0;
}

switch(true) {
case $a > $b:
...
case $c == "hello":
...
...

sponsored by the PHPepsi community